x^2+200x+1875=0

Solution for x^2+200x+1875=0 equation:

x^2+200x+1875=0

a = 1; b = 200; c = +1875;
Δ = b2-4ac
Δ = 2002-4·1·1875
Δ = 32500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32500}=\sqrt{2500*13}=\sqrt{2500}*\sqrt{13}=50\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-50\sqrt{13}}{2*1}=\frac{-200-50\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+50\sqrt{13}}{2*1}=\frac{-200+50\sqrt{13}}{2}
$